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S Feb 9, 2017 at 3:34 history suggested Richard Chapling CC BY-SA 3.0
corrected errors
Feb 9, 2017 at 2:32 review Suggested edits
S Feb 9, 2017 at 3:34
Dec 28, 2014 at 14:42 history edited Avshalom CC BY-SA 3.0
better text
Dec 22, 2014 at 21:34 history edited Avshalom CC BY-SA 3.0
French
Dec 22, 2014 at 20:26 history edited Avshalom CC BY-SA 3.0
spelling
Dec 22, 2014 at 20:13 history edited Avshalom CC BY-SA 3.0
details of Sierpinski's argument
Dec 22, 2014 at 17:36 comment added Asaf Karagila If you want to be correct, $[\Bbb R]^{\aleph_0}$, since $|\Bbb R|^{\aleph_0}=|\Bbb R|$ requires no choice whatsoever.
Dec 22, 2014 at 17:09 history edited Avshalom CC BY-SA 3.0
small details
Dec 22, 2014 at 16:53 history edited Avshalom CC BY-SA 3.0
update to reflect Ashitosh's sumary
Dec 22, 2014 at 16:18 history edited Avshalom CC BY-SA 3.0
spelling
Dec 22, 2014 at 16:18 history undeleted Avshalom
Dec 22, 2014 at 16:15 history deleted Avshalom via Vote
Dec 22, 2014 at 16:11 history answered Avshalom CC BY-SA 3.0