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Dec 17, 2014 at 9:58 vote accept McDuffin
Dec 14, 2014 at 23:08 comment added Joel David Hamkins Yes, of course I agree completely with that.
Dec 14, 2014 at 23:07 comment added Emil Jeřábek I agree with the sentiment, though I'd prefer to say that the existence of a transitive model is (in the realm of set theory) much stronger than the existence of an $\omega$-model, which is in turn much stronger than $\omega$-consistency.
Dec 14, 2014 at 20:23 history edited Joel David Hamkins CC BY-SA 3.0
Improved exposition
Dec 14, 2014 at 20:17 comment added Joel David Hamkins One might add, however, that in the large cardinal realm this difference doesn't actually count as very much stronger. Typically, a stronger large cardinal provides a full transitive model of the weaker cardinals.
Dec 14, 2014 at 16:10 history edited Joel David Hamkins CC BY-SA 3.0
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Dec 14, 2014 at 16:07 comment added Joel David Hamkins Yes, you are right. I have edited.
Dec 14, 2014 at 15:58 comment added Emil Jeřábek The existence of an $\omega$-model is equivalent to consistency in $\omega$-logic, which is a much stronger property than just $\omega$-consistency.
Dec 14, 2014 at 15:56 history edited Joel David Hamkins CC BY-SA 3.0
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Dec 14, 2014 at 15:44 history edited Joel David Hamkins CC BY-SA 3.0
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Dec 14, 2014 at 15:31 history answered Joel David Hamkins CC BY-SA 3.0