Timeline for Equation for non-invertible elements in Clifford algebras
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 14, 2014 at 7:49 | vote | accept | Jjm | ||
| Dec 13, 2014 at 17:34 | comment | added | Qiaochu Yuan | The Clifford algebra case follows more or less directly from the matrix case (even if you didn't have Johannes Ebert's observation below) because Clifford algebras are semisimple, and so are finite products of matrix algebras (over division rings). | |
| Dec 13, 2014 at 15:47 | answer | added | Johannes Ebert | timeline score: 11 | |
| Dec 13, 2014 at 14:26 | history | asked | Jjm | CC BY-SA 3.0 |