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Dec 14, 2014 at 9:35 vote accept asd
Dec 13, 2014 at 14:07 answer added Alexandre Eremenko timeline score: 5
Dec 13, 2014 at 13:51 comment added asd @Alex: In Euclidean plane this problem (from the comment above) would mean to construct two n-gons with same interior angles, area and perimeter. This problem is easily solved. In spherical case this is less obvious to me.
Dec 13, 2014 at 13:42 comment added asd Thank you for your comments, I will be more precise. First, it would help me to know if there are non isometric n-gons with $n\geq 4$ with same interior angles $\alpha_1,…,\alpha_n$ and same perimeter (i.e. sum of the side lengths) $a_1+…+a_n$. E.g. for n=4 I could construct a one parameter family of non isometric 4-gons with same interior angles, but which all have different perimeter. Are there two 4-gone which not only have the same interior angles but also the same perimeter?
Dec 13, 2014 at 12:27 comment added Joonas Ilmavirta You can triangulate any polygon with more than three vertices. This helps reduce some problems for general polygons (like the sum of angles as a function of area) to those with triangles, but it's hard to say more before you specify your question.
Dec 13, 2014 at 11:50 comment added Alex Degtyarev In the case of more than three vertices you have more than $0$ degrees of freedom. What kind of classification are you looking for? E.g., what would the Euclidean counterpart be?
Dec 13, 2014 at 11:41 review First posts
Dec 13, 2014 at 11:50
Dec 13, 2014 at 11:41 history asked asd CC BY-SA 3.0