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Jun 22, 2022 at 7:16 history edited CommunityBot
replaced http://front.math.ucdavis.edu/ with https://arxiv.org/abs/
Dec 13, 2014 at 6:15 comment added Christian Remling Existence of $C$ (effective or not) is enough to answer the OP's question as posed.
Dec 13, 2014 at 4:34 comment added NAME_IN_CAPS Also, I think Zhang had instead of $[x,2x]$, an interval something like $[x,x+x/L(x)]$ where $L(x)$ was some power of $\log\log x$ IIRC. Likely Maynard's argument can show the same.
Dec 13, 2014 at 3:35 comment added NAME_IN_CAPS Does Maynard tell us how "sufficiently large" $x$ must be, or is the result ineffective as stated (one can peel away the exceptional modulus from the large sieve mechanism, but my guess is that Maynard does not do this explicitly)? Or to rephrase more in terms of the original question/answer: is your $C$ effectively computable, or have you just shown the existence of $f(n)$ w/o an explicit function?
Dec 13, 2014 at 3:18 comment added Jason Rute That was a much better bound than I expected!
Dec 13, 2014 at 3:13 vote accept Jason Rute
Dec 13, 2014 at 3:09 history answered Jeremy Rouse CC BY-SA 3.0