Skip to main content

Timeline for A question regarding $ZFC^{-}$

Current License: CC BY-SA 3.0

16 events
when toggle format what by license comment
Dec 22, 2014 at 2:41 comment added François G. Dorais In that case, the powerset axiom is really hard to beat!
Dec 22, 2014 at 1:56 history edited Thomas Benjamin CC BY-SA 3.0
improved formatting
Dec 22, 2014 at 1:33 history edited Thomas Benjamin CC BY-SA 3.0
improved formatting
Dec 22, 2014 at 1:30 comment added Thomas Benjamin @FrançoisG.Dorais: Since there a great deal of such sets of axioms, the simplest and most 'economical' (i.e. the set with the fewest number of axioms) will do just fine, thank you.
Dec 22, 2014 at 1:23 history edited Thomas Benjamin CC BY-SA 3.0
revised question in light of new information
Dec 13, 2014 at 14:04 comment added François G. Dorais Replacement is basically a special case of collection. Depending on how it is formulated, collection might give you a set that is larger than the range of your function, but you can always trim it down using comprehension.
Dec 13, 2014 at 10:06 comment added Thomas Benjamin @FrançoisG.Dorais: Can you prove that Replacement is a consequence of $ZFC^{-}$?
Dec 13, 2014 at 3:59 answer added François G. Dorais timeline score: 2
Dec 13, 2014 at 2:59 comment added François G. Dorais There are a great deal of such sets, so you probably need to be more specific.
Dec 13, 2014 at 2:37 comment added Thomas Benjamin @FrançoisG.Dorais: Simply put, I am looking for some set of sentences in the language of set theory that will derive Powerset. Perhaps such a set does not exist, but it does not hurt to look. Perhaps some references of work done in this area will be a good start for me.
Dec 13, 2014 at 2:18 comment added François G. Dorais Since powerset is a reasonably simple sentence, I can't really see what you're asking for.
Dec 13, 2014 at 2:13 comment added Thomas Benjamin @FrançoisG.Dorais: Very well, then. So the question now becomes, what axioms $X$ (other than the trivial axiom Powerset) when added to $ZFC^{-}$, will derive Powerset as a theorem, and recover full ZFC? Thanks for the info, by the way. It is very much appreciated.
Dec 13, 2014 at 2:08 comment added François G. Dorais I was using your definition.
Dec 13, 2014 at 2:06 comment added Thomas Benjamin @FrançoisG.Dorais: ZFC- is ZFC-Powerset, correct? If so then this is different than $ZFC^{-}$.
Dec 13, 2014 at 1:48 comment added François G. Dorais Replacement is a consequence of ZFC-.
Dec 13, 2014 at 1:14 history asked Thomas Benjamin CC BY-SA 3.0