Timeline for A ring of invariants in characteristic 2
Current License: CC BY-SA 2.5
3 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 22, 2010 at 15:21 | history | edited | damiano | CC BY-SA 2.5 |
added 861 characters in body
|
| Mar 22, 2010 at 5:17 | comment | added | Torsten Ekedahl | The characteristic certainly plays a role in the answer. For all characteristics but two the invariant ring is Cohen-Macaulay but in characteristic two it isn't. It is of course true that you might find a (more or less) characteristic free presentation of the invariant ring where this fact is not apparent. | |
| Mar 21, 2010 at 9:45 | history | answered | damiano | CC BY-SA 2.5 |