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Feb 3, 2015 at 7:30 comment added Norbert Anyway, great thanks for thinking about my problem.
Feb 3, 2015 at 6:24 comment added Narutaka OZAWA Indeed, you're right. My proof does not stand.
Feb 2, 2015 at 20:12 comment added Norbert Unfortunately, I do not understand one step of your proof. Why is $\Psi^*$ continuous? The continuity of $\Phi^*$ is clear, but the operation of total variation doesn't preserve weak convergence of measures so I don't see why $\Psi^*(x)=\frac{|\Phi^*(x)|}{\Vert\Phi^*(x)\Vert}$ must be continuous. Could you explain that step?
Jan 25, 2015 at 9:33 comment added Norbert Thank you prof. Ozawa and excuse me for such late reply.
Jan 23, 2015 at 18:12 vote accept Norbert
Feb 2, 2015 at 20:01
Dec 7, 2014 at 5:00 history answered Narutaka OZAWA CC BY-SA 3.0