Timeline for $\zeta(0)$ and the cotangent function
Current License: CC BY-SA 3.0
10 events
when toggle format | what | by | license | comment | |
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Dec 20, 2014 at 18:04 | vote | accept | GH from MO | ||
Dec 6, 2014 at 20:49 | history | edited | GH from MO | CC BY-SA 3.0 |
added 1 character in body
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Dec 6, 2014 at 20:22 | history | edited | GH from MO | CC BY-SA 3.0 |
deleted 5 characters in body
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Dec 6, 2014 at 20:09 | history | edited | GH from MO | CC BY-SA 3.0 |
edited body
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Dec 6, 2014 at 19:54 | comment | added | juan | @GH from MO I have added a little explanation about how (4) implies (5) for $\sigma<0$ | |
Dec 6, 2014 at 19:54 | history | edited | juan | CC BY-SA 3.0 |
added 401 characters in body
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Dec 6, 2014 at 12:40 | comment | added | GH from MO | Thanks! I also like your proof, I find (7) natural and revealing. Can you add more detail, for the sake of the readers, how (4) implies (5)? I agree that a simpler proof might exist. Let us wait two weeks, and if there is no better proof, I will accept this one officially. | |
Dec 6, 2014 at 12:32 | comment | added | godelian | Given the fact that what you end up explaining why the series, considered as a Laurent series, predicts also the values of $\zeta$ at the negative even numbers, I think this proof is as simple as it reasonably can be expected to be. This because you are forced to consider the analytic continuation of $\zeta$ to the left half plane, not just to the critical strip, so it's reasonable that the functional equation is invoked. | |
Dec 6, 2014 at 12:08 | history | edited | Emil Jeřábek | CC BY-SA 3.0 |
fix markup
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Dec 6, 2014 at 11:23 | history | answered | juan | CC BY-SA 3.0 |