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Dec 6, 2014 at 2:56 comment added John Baez Thanks! If we think of the Coxeter group concretely as transformations of $\mathbb{R}^8$, the only central element is $x \mapsto -x$. Then this outer automorphism must be $w \mapsto \det(w) w$: i.e., it does nothing to even products of reflections through roots, and multiplies odd products by $-1$. Sound right?
Dec 5, 2014 at 19:16 history edited Qiaochu Yuan CC BY-SA 3.0
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Dec 5, 2014 at 19:04 history edited Qiaochu Yuan CC BY-SA 3.0
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Dec 5, 2014 at 18:54 history answered Qiaochu Yuan CC BY-SA 3.0