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Dec 15, 2014 at 4:21 vote accept mdg
S Dec 15, 2014 at 4:20 history bounty ended mdg
S Dec 15, 2014 at 4:20 history notice removed mdg
Dec 9, 2014 at 11:20 answer added user80744 timeline score: 11
Dec 8, 2014 at 20:07 history edited mdg CC BY-SA 3.0
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Dec 8, 2014 at 17:39 comment added Pedro Lauridsen Ribeiro An implicit assumption in the question is that the base manifold $M$ should be compact, otherwise the operator cannot be Fredholm. Moreover, one only gets the tame estimates needed for Nash-Moser under this assumption. It is satisfied in the examples given, but it's not explicitly stated.
Dec 8, 2014 at 17:35 answer added Deane Yang timeline score: 7
Dec 8, 2014 at 11:03 comment added Igor Khavkine If you use the inclusion $i \colon \operatorname{ker} P \to \Gamma(\cdots)$ and the orthogonal projection $j \colon \Gamma(\cdots) \to \operatorname{coker} P$, then $G$ is precisely the "pseudoinverse" that I mentioned in my answer. Other choices of $i, j, M$ and $N$ simply parametrize the many different ways one can define an "inverse" of a non-invertible linear operator. That last issue has nothing in particular to do with elliptic operators or functional analysis. It is an issue of ordinary linear algebra.
Dec 8, 2014 at 9:46 comment added mdg So I think the second question is the same as the first - I'd like to construct the Green's operator of $P$.
Dec 8, 2014 at 9:17 comment added mdg Basically I'm trying to verify a step in a paper by Hamilton, which essentially says "use the Green's operator" of the map $P$ above. One can only assume that by the Green's operator of $P$, Hamilton means the definition in his paper in the Nash-Moser theorem, which is written at about the same time as the paper I'm reading.
Dec 8, 2014 at 9:11 comment added Igor Khavkine Your additional question is substantially different from the original, since you seem to be interested in the Nash-Moser inverse function theorem now. I suggest you ask it as a separate question. Also, you haven't made it clear how you intend to interpret the inverse (aka the Green operator) or a non injective/surjective differential operator.
S Dec 8, 2014 at 5:09 history bounty started mdg
S Dec 8, 2014 at 5:09 history notice added mdg Authoritative reference needed
Dec 8, 2014 at 5:07 history edited mdg CC BY-SA 3.0
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Dec 5, 2014 at 21:28 history edited Vít Tuček CC BY-SA 3.0
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Dec 4, 2014 at 17:56 answer added Igor Khavkine timeline score: 4
Dec 4, 2014 at 12:17 history edited user9072 CC BY-SA 3.0
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Dec 4, 2014 at 12:05 answer added asv timeline score: 3
Dec 4, 2014 at 7:00 history edited mdg CC BY-SA 3.0
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Dec 4, 2014 at 5:23 history edited mdg CC BY-SA 3.0
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Dec 4, 2014 at 5:13 history edited mdg CC BY-SA 3.0
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Dec 4, 2014 at 3:51 history edited mdg
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Dec 4, 2014 at 3:41 history asked mdg CC BY-SA 3.0