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Dec 5, 2014 at 9:35 vote accept Dominic van der Zypen
Dec 5, 2014 at 9:20 answer added Eric Wofsey timeline score: 8
Dec 5, 2014 at 9:02 answer added Qiaochu Yuan timeline score: 3
Dec 3, 2014 at 6:11 comment added Qiaochu Yuan If you can construct a graph $G$ such that $|\text{Hom}(X, G)|$ is always either empty or infinite, then I think you can take $H = G \times G$, and for most $G$ this should be a counterexample. (I'm not sure which graph product you need for the universal property in this setting.)
Dec 2, 2014 at 14:18 review Close votes
Dec 2, 2014 at 17:16
Dec 2, 2014 at 13:50 history asked Dominic van der Zypen CC BY-SA 3.0