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S Dec 5, 2014 at 9:42 history suggested Tomasz Kania CC BY-SA 3.0
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Dec 5, 2014 at 9:31 review Suggested edits
S Dec 5, 2014 at 9:42
Dec 4, 2014 at 19:25 answer added Tomasz Kania timeline score: 6
Dec 1, 2014 at 15:16 vote accept Tom
Dec 1, 2014 at 15:13 answer added user62448 timeline score: 14
Dec 1, 2014 at 15:09 comment added M.González $E/F$ is isomorphic to each one-codimensional closed subspace of $E$, and does not need to be isomorphic to $E$. For example, when $E$ is the hereditarily indecomposable space of Gowers and Maurey, $E/F$ is not isomorphic to $E$.
Dec 1, 2014 at 14:53 history edited Loïc Teyssier CC BY-SA 3.0
edited body
Dec 1, 2014 at 14:41 comment added Tom Thanks for your comment. I meant topological isomorphisms and edited the question accordingly.
Dec 1, 2014 at 14:40 history edited Tom CC BY-SA 3.0
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Dec 1, 2014 at 14:15 comment added Simon Henry By isomorphism, you mean isometrically isomorph or linear continuous bijection (whose inverse is hence also going to be continuous) ?
Dec 1, 2014 at 13:39 history asked Tom CC BY-SA 3.0