One can rewrite the problem in terms of products of i.i.d. random variables as follows.
Assume that $X_t$ has distribution density $f_t$. Then, the relation between $f_t$ and $f_{t+1}$ means that one can choose $X_{t+1}=X_tZ_{t+1}$, where the $Z_t$ are i.i.d. and $Z_t=A$ or $B$ or $A+B$, with probabilities $p_{12}A$, $p_{21}B$ and $p_{22}(A+B)$, respectively.
Hence, for the relation between $f_t$ and $f_{t+1}$ to make sense, one must assume that the three nonnegative numbers $p_{12}A$, $p_{21}B$ and $p_{22}(A+B)$ sum to $1$ for the relation between $f_t$ and $f_{t+1}$ to make sense, and when this is so, $X_t=X_0Z_1Z_2\cdots Z_t$.
This tells you that $E(X_t)=E(X_0)m^t$ for every $t$, with $m=E(Z_1)$, that is, $m=p_{12}A^2+p_{21}B^2+p_{22}(A+B)^2$; that $t^{-1}\log X_t$ converges almost surely to $\mu=E(\log Z_t)$, that is, $\mu=p_{12}A\log A+p_{21}B\log B+p_{22}(A+B)\log(A+B)$; and that $\log X_t$ follows the multinomial distribution with parameters $t$ and $(p_{12}A,p_{21}B,p_{22}(A+B))$ (or more precisely, the convolution of this with the distribution of $\log X_0$).:
Unfortunately, these remarks do not help much if one is interested in closed form formulas. Sorry.
- $E(X_t)=E(X_0)m^t$ for every $t$, with $m=E(Z_1)$, that is, $$ m=p_{12}A^2+p_{21}B^2+p_{22}(A+B)^2. $$
- $t^{-1}\log X_t$ converges almost surely to $\mu=E(\log Z_1)$, that is, $$ \mu=p_{12}A\log A+p_{21}B\log B+p_{22}(A+B)\log(A+B). $$
- $\log X_t$ follows the multinomial distribution with parameters $t$ and $(p_{12}A,p_{21}B,p_{22}(A+B))$, or, more precisely, the convolution of this multinomial with the distribution of $\log X_0$.