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Dec 23, 2014 at 2:32 vote accept user6818
Nov 30, 2014 at 22:24 answer added Delio Mugnolo timeline score: 2
Nov 29, 2014 at 5:56 answer added Son P Nguyen timeline score: 1
Nov 29, 2014 at 4:26 answer added Chris Godsil timeline score: 17
Nov 29, 2014 at 1:56 comment added Aaron Meyerowitz $L_2$ is not the same kind of graph Laplacian as $L_1$. When one is going to be using both kinds, it is common to call $L_2$ the normalized Laplacian matrix and $L_1$ the standard Laplacian matrix. With certain exceptions (find them!) a normalized Laplacian is not a standard Laplacian. Read the article to see some common properties.
Nov 29, 2014 at 1:08 comment added user6818 @AaronMeyerowitz So $L_2$ is not a graph Laplacian - right?
Nov 29, 2014 at 0:22 comment added Aaron Meyerowitz In the middle option you want the diagonal entries to be $1$ (or $0$ in the case of degree $0$ vertices, if any) The Wikipedia article en.wikipedia.org/wiki/Laplacian_matrix explains the connections. $L_1=L_3$ and $L_2=SL_1S$ where $S=\sqrt{D}$ is the diagonal matrix with (non-negative) entries $\sqrt{\deg(v_i)}.$
Nov 28, 2014 at 23:02 comment added user6818 oh - sorry - changed it!
Nov 28, 2014 at 23:02 comment added Qiaochu Yuan What's a reference for the third? Are you sure you don't want $A$ to be the incidence matrix?
Nov 28, 2014 at 22:58 history asked user6818 CC BY-SA 3.0