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Dec 11, 2014 at 19:30 comment added Eramol @BenBarber It is stated in the algorithm (see paper here ), that if there is no feasible solution, the edges from/to S'/T' will not be saturated. But here it's not the case. Existence of one legal flow is not enough. Imagine the graph above with one more edge without requirements - that's a one legal flow you needed.
S Dec 11, 2014 at 11:23 history suggested Ben Barber
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Dec 11, 2014 at 10:41 comment added Ben Barber One obvious problem is that there are no legal flows through that graph. Does the algorithm perhaps require the existence of at least one legal flow? What presentation of the algorithm are you working from?
Dec 11, 2014 at 10:37 review Suggested edits
S Dec 11, 2014 at 11:23
Dec 10, 2014 at 10:36 history edited Eramol CC BY-SA 3.0
added 3 characters in body
Nov 28, 2014 at 15:48 history edited Joonas Ilmavirta CC BY-SA 3.0
Included the linked image.
Nov 28, 2014 at 15:35 review First posts
Nov 28, 2014 at 15:40
Nov 28, 2014 at 15:32 history asked Eramol CC BY-SA 3.0