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Dec 3, 2014 at 9:25 history edited Thomas Richard CC BY-SA 3.0
added 104 characters in body
Dec 3, 2014 at 9:18 comment added Thomas Richard My bad. This case is integrable actually.
Dec 3, 2014 at 5:35 comment added Ali :your example simply does not work as one can clearly see that the inner products DO vanish everywhere actually as I also mentioned above. Anyways one can indeed find many examples where the system has no solution. Thanks for your comment
Dec 2, 2014 at 9:16 history edited Thomas Richard CC BY-SA 3.0
Added the fact that the solution needs to be non constant.
Dec 2, 2014 at 9:14 comment added Thomas Richard Ok, I did the computation: if $u$ solves the problem, so does any $f(u)$ for $f$ a smooth function from $\mathbb{R}$ to $\mathbb{R}$. So I'll take $u(x,y,z)=z^2-y^2$ instead of yours. Then $\nabla\phi_1=\partial_x$ and $\nabla\phi_2=yz\partial_x+xz\partial_y+xy\partial_z$, while $\nabla u= 2z\partial_z-2y\partial_y$. On can check that the inner products between the gradients don't vanish everywhere.
Nov 29, 2014 at 7:26 comment added Thomas Richard I'll have a look but I'm skeptical.
Nov 29, 2014 at 1:35 comment added Ali It is clear that u solves the aforementioned system of odes in the question in euclidean space
Nov 29, 2014 at 1:34 comment added Ali I am not sure what I am missing here...I agree with the condition you have mentioned but I am not sure the example works.. to make this clear take $ u(x_1,x_2,x_3) = e^{\frac{x_3^2-x_2^2}{2}}$
Nov 29, 2014 at 1:13 vote accept Ali
Nov 29, 2014 at 1:32
Nov 28, 2014 at 16:17 vote accept Ali
Nov 29, 2014 at 1:10
Nov 28, 2014 at 9:39 history answered Thomas Richard CC BY-SA 3.0