Timeline for a question about connected open sets in $R^2$
Current License: CC BY-SA 3.0
24 events
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Nov 27, 2014 at 15:56 | comment | added | user173856 | OK,now the question is still the original version!I start a new question and in my new question I link this one.Here is my new question: mathoverflow.net/questions/188225/…. | |
Nov 27, 2014 at 15:34 | vote | accept | user173856 | ||
Nov 27, 2014 at 15:34 | vote | accept | user173856 | ||
Nov 27, 2014 at 15:34 | |||||
Nov 27, 2014 at 15:34 | vote | accept | user173856 | ||
Nov 27, 2014 at 15:34 | |||||
Nov 27, 2014 at 15:34 | history | edited | user173856 | CC BY-SA 3.0 |
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Nov 27, 2014 at 15:31 | comment | added | Mirko | if someone provides a nice answer to the modified question you would have a difficult dilemma to solve, namely which of the more that one deserving answers to accept. (If you start a new question you should probably link this one to the new one, or link them both ways). | |
Nov 27, 2014 at 15:26 | history | edited | user173856 | CC BY-SA 3.0 |
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Nov 27, 2014 at 15:19 | comment | added | Todd Trimble | Please don't modify your question, for which answers were thoughtfully provided. Best would be to ask your modified question in another post, but at least retain the text of your original question, and add your modification as an edit if you really don't want to start another post. | |
Nov 27, 2014 at 15:13 | history | edited | user173856 | CC BY-SA 3.0 |
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Nov 27, 2014 at 15:12 | history | edited | Stanley Yao Xiao | CC BY-SA 3.0 |
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Nov 27, 2014 at 15:12 | comment | added | user173856 | Sorry,I just modified my question! | |
Nov 27, 2014 at 15:11 | history | edited | user173856 | CC BY-SA 3.0 |
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Nov 27, 2014 at 14:32 | answer | added | S. Carnahan♦ | timeline score: 6 | |
Nov 27, 2014 at 14:31 | answer | added | Emil Jeřábek | timeline score: 13 | |
Nov 27, 2014 at 13:24 | comment | added | Emil Jeřábek | Sorry, you are right. | |
Nov 27, 2014 at 13:15 | comment | added | Tom Leinster | Oh, oops. I misread it. | |
Nov 27, 2014 at 13:14 | comment | added | Joonas Ilmavirta | @TomLeinster, the OP assumes $\emptyset\neq U\subset V$. | |
Nov 27, 2014 at 13:12 | comment | added | Tom Leinster | Surely the answer is an easy "no". Just take $U$ and $V$ to be disjoint. Am I missing something? | |
Nov 27, 2014 at 12:53 | comment | added | Włodzimierz Holsztyński | @EmilJeřábek, $\ U\ $ is supposed to be connected. | |
Nov 27, 2014 at 11:57 | review | Close votes | |||
Nov 27, 2014 at 19:51 | |||||
Nov 27, 2014 at 11:49 | comment | added | Beni Bogosel | You could reformulate as follows: does there exist an open set $U$ such that for every ball $B$ which incersects $U$, but is not contained in $U$, the set $B\cap U$ is disconnected? | |
Nov 27, 2014 at 11:24 | history | undeleted | user173856 | ||
Nov 27, 2014 at 11:24 | history | deleted | user173856 | via Vote | |
Nov 27, 2014 at 11:23 | history | asked | user173856 | CC BY-SA 3.0 |