Timeline for abelian p- subgroups of E_6(q)
Current License: CC BY-SA 3.0
8 events
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Nov 28, 2014 at 14:40 | comment | added | Jim Humphreys | @Nick: In this case the structure of the root groups (and the simple multiplication/commutation rules independent of $q$) come into play, along with the fact that 16 is the maximum number of "commuting" positive roots (earlier work of Mal'cev). I don't know a more explicit reference beyond Vdovin and GLS, but there may be one. | |
Nov 27, 2014 at 17:29 | comment | added | Nick Gill | Jim, one query. I don't have GLS3 in front of me but, from memory, their results describe the *maximal possible rank of an elementary abelian $p$-subgroup, as opposed to the possible ranks of a maximal elementary abelian $p$-subgroup. (In theory there could be different maximal elementary abelian $p$-subgroups with different ranks, couldn't there?) | |
Nov 27, 2014 at 9:13 | vote | accept | darya | ||
Nov 27, 2014 at 1:48 | comment | added | Peter McNamara | Well once p is sufficiently large, all unipotent elements of E_6(F_q) have order p so the notion of maximal abelian subgroup and maximal elementary abelian subgroup coincide. | |
Nov 26, 2014 at 23:47 | history | edited | Jim Humphreys | CC BY-SA 3.0 |
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Nov 26, 2014 at 23:44 | vote | accept | darya | ||
Nov 27, 2014 at 9:13 | |||||
Nov 26, 2014 at 21:44 | history | edited | Jim Humphreys | CC BY-SA 3.0 |
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Nov 26, 2014 at 21:34 | history | answered | Jim Humphreys | CC BY-SA 3.0 |