Timeline for abelian p- subgroups of E_6(q)
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 27, 2014 at 9:13 | vote | accept | darya | ||
| Nov 26, 2014 at 23:44 | vote | accept | darya | ||
| Nov 27, 2014 at 9:13 | |||||
| Nov 26, 2014 at 21:34 | answer | added | Jim Humphreys | timeline score: 2 | |
| Nov 26, 2014 at 16:23 | comment | added | Nick Gill | You can use Chevalley's commutator formula to figure out which of the root groups commute - it's conceivable I suppose that all maximal abelian unipotents are conjugates of these.... Also, the abelian unipotent subgroups of maximal order were classified by Mal'cev I believe. See the references in this paper: math.nsc.ru/~vdovin/evdavg.ps | |
| Nov 26, 2014 at 3:18 | comment | added | darya | I'm sorry, I mean maximal abelian p-subgroups. | |
| Nov 26, 2014 at 3:16 | history | edited | darya | CC BY-SA 3.0 |
deleted 6 characters in body; edited title
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| Nov 26, 2014 at 1:57 | comment | added | Jim Humphreys | The formulation is unclear, since this group doesn't have abelian Sylow $p$-subgroups. | |
| Nov 25, 2014 at 23:29 | history | asked | darya | CC BY-SA 3.0 |