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Timeline for Continuity of a Functional

Current License: CC BY-SA 3.0

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Nov 26, 2014 at 18:22 vote accept Dinesh
Nov 26, 2014 at 18:22 vote accept Dinesh
Nov 26, 2014 at 18:22
Nov 26, 2014 at 17:57 answer added Martin Hairer timeline score: 1
Nov 26, 2014 at 11:33 comment added Dinesh So, basically, $M$ can be considered as having support $[\alpha,1-\alpha],\alpha>0$
Nov 26, 2014 at 11:32 history edited Dinesh CC BY-SA 3.0
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Nov 26, 2014 at 11:19 comment added Dinesh @MartinHairer, thank you very much for your remark. That was a mistake, sorry. I am in fact looking at the integral to $T_{sup}(F)=\sup_{\{M\in\frak{M}\}}\{\int_{[\alpha,1-\alpha]}F^{-1}(s)M(ds)\}$ for $\alpha>0$
Nov 26, 2014 at 11:17 history edited Dinesh CC BY-SA 3.0
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Nov 26, 2014 at 10:39 comment added Martin Hairer You'll certainly need some additional assumptions since $F^{-1}$ typically diverges near $0$ and $1$, so that $T$ can easily be infinite. This is extremely unstable under weak convergence of the CDF $F$, so that $T$ cannot be continuous if $M$ has support at $0$ or at $1$.
Nov 26, 2014 at 2:36 history edited Dinesh CC BY-SA 3.0
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Nov 26, 2014 at 2:35 comment added Dinesh @MartinHairer, yes, sorry. I mean CDF. And, also, yes, weak convergence.
Nov 25, 2014 at 21:48 comment added Martin Hairer When you say that the domain are 'random variables', do you mean 'cumulative distribution functions'? What topology do you want on these? (Presumably weak convergence for the corresponding probability measures?)
Nov 25, 2014 at 16:05 comment added Dinesh @JochenWengenroth, Sorry, I avoided details as I thought the details might not effect the result. I have added details if that can help.
Nov 25, 2014 at 16:03 history edited Dinesh CC BY-SA 3.0
Details Added
Nov 25, 2014 at 15:05 comment added Jochen Wengenroth The question is not clear. What is the domain of $T$? Do you mean by $F^{-1}(s)$ the multiplicative inverse $1/F(s)$?
Nov 25, 2014 at 13:16 review First posts
Nov 25, 2014 at 13:25
Nov 25, 2014 at 13:14 history asked Dinesh CC BY-SA 3.0