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Nov 24, 2014 at 11:09 vote accept Michael Andrew Bentley
Nov 24, 2014 at 5:50 answer added Carlo Beenakker timeline score: 1
Nov 23, 2014 at 23:14 comment added Michael Andrew Bentley Thanks Carlo, but please could you clarify a bit more how you arrived at that? Your answer looks intuitively appealing, but when I try to solve for $h(y,x)$ myself I arrive at an ugly answer! I've not found any examples where people use the form I'm looking for, is there a reason do you think? Thanks for the help.
Nov 23, 2014 at 21:15 comment added Carlo Beenakker certainly: $h(y,x)=v(y)\partial_y \delta(x-y)$
Nov 23, 2014 at 20:53 history asked Michael Andrew Bentley CC BY-SA 3.0