Timeline for Conjecture regarding closest point inside a discrete ball to a line
Current License: CC BY-SA 3.0
13 events
when toggle format | what | by | license | comment | |
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Nov 23, 2014 at 9:52 | comment | added | Rob | lol. Yes you are right. | |
Nov 23, 2014 at 9:51 | history | edited | Rob | CC BY-SA 3.0 |
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Nov 23, 2014 at 3:24 | comment | added | KConrad | You mean "fleshed out," not "flushed out." | |
Nov 23, 2014 at 0:56 | comment | added | Hao Chen | I finally got my own proof complete, and propose a fix to your proof, see my revised answer. | |
Nov 22, 2014 at 23:37 | comment | added | Hao Chen | Nah, I'm not ... see my answer. | |
Nov 22, 2014 at 22:50 | comment | added | Hao Chen | Sorry, I'm now OK with your proof. | |
Nov 22, 2014 at 21:36 | comment | added | Hao Chen | I'm not saying that the proof is wrong. But this is a detail that bothers me. | |
Nov 22, 2014 at 21:22 | comment | added | Hao Chen | In your picture, P is not the closest to l. There are closer points on the other side, for example (1, 1). By symmetry, (-1, -1) is a closer point below l with larger angle (or not depending on your meaning by angle). | |
Nov 22, 2014 at 21:16 | comment | added | Rob | You mean in the lower half plane? By symmetry, $(n,m) \in \mathbb{Z}^2$ is a minimizer of the orthogonal distance to $\ell$ iff $(-n,-m)$ is. Therefore it suffices to consider the upper half plane. | |
Nov 22, 2014 at 21:11 | comment | added | Hao Chen | What about the area between the parallel lines OQ and PR, with m<0 ? | |
Nov 22, 2014 at 20:44 | history | edited | Rob | CC BY-SA 3.0 |
added 265 characters in body
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Nov 22, 2014 at 20:14 | history | edited | Rob | CC BY-SA 3.0 |
added 24 characters in body
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Nov 22, 2014 at 20:03 | history | answered | Rob | CC BY-SA 3.0 |