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Nov 21, 2014 at 11:52 vote accept acr
Nov 20, 2014 at 23:10 answer added Matthias Ludewig timeline score: 10
Nov 20, 2014 at 22:20 comment added acr @Steven Gubkin It is discussed briefly in arxiv:0704.2833 (see the 2nd page). To see it in $\mathbb{R}^2$ you can cancel the terms of the form $(\partial^2 f/\partial x_i^2)^2$ from both sides and then judiciously apply integration by parts to each of the remaining terms: this results in a portion that cancels (as $f$ is compactly supported) and the integral of the product of a first and third derivative.
Nov 20, 2014 at 21:48 history asked acr CC BY-SA 3.0