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Dec 21, 2014 at 16:28 comment added Noam D. Elkies It tells you something that's not obvious from the original definition: the surface in question is embedded in ${\bf C}^g$ and periodic. For $g=2$ we even learn that it's the zero-set of $\Theta$.
Nov 21, 2014 at 1:12 comment added Mohammad Farajzadeh-Tehrani Sure, but this is as abstract as the original definition.
Nov 20, 2014 at 17:30 review Late answers
Nov 20, 2014 at 17:40
Nov 20, 2014 at 17:10 history answered Holonomia CC BY-SA 3.0