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Nov 26, 2014 at 22:05 vote accept Rich Apodaca
Nov 20, 2014 at 19:14 comment added Joe Silverman @RichApodaca The process is very feasible, in the following sense. I'll describe one case. Often $E(\mathbb{R})$ is isomorphic as a group to $\mathbb{R}^*/q^{\mathbb Z}$ for a real $q$ that's easy to compute to lots of decimal places. Further, the isomorphism is given by an explicit, rapidly converging series. So we have an isomorphism $f:\mathbb{R}^*/q^{\mathbb Z}\to E(\mathbb{R})$. You're taking a point $P\in E(\mathbb{R})$ and asking to solve $f(nt)=P$. So it's really a problem of numerical analysis: how easily can one solve such equations for an explicit power series $f(t)$?
Nov 20, 2014 at 18:30 comment added Rich Apodaca @ChrisWuthrich, sage's division_points function was helpful (although I'm not a sage user). I'm not so much interested in finding a procedure as understanding how feasible the process is. For example, how does division_points perform as n and the coordinates of P increase in value?
Nov 20, 2014 at 18:18 comment added Rich Apodaca @FelipeVoloch, thanks for the insight. What are the options for dividing by an odd number?
Nov 20, 2014 at 17:21 comment added Chris Wuthrich If you are looking for "procedures" to compute it for general fields, then look at sage's function P.division_points(n). It starts by finding roots of the division polynomial in the field.
Nov 20, 2014 at 17:20 review Close votes
Nov 22, 2014 at 16:39
Nov 20, 2014 at 17:07 answer added Joe Silverman timeline score: 10
Nov 20, 2014 at 17:02 comment added Felipe Voloch Over the reals there are elliptic logarithms and elliptic exponentials that convert the problem to division in real numbers. The only issue is that you can only divide by 2 (or any even number) if you are in the connected component of the identity. This is not an MO question, though.
Nov 20, 2014 at 16:37 review First posts
Nov 20, 2014 at 17:24
Nov 20, 2014 at 16:35 history asked Rich Apodaca CC BY-SA 3.0