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Chris Gerig
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Yes, given two contact 3-manifolds $(M_1,\xi_1)$ and $(M_2,\xi_2)$ we can form their contact sum $(M_1\# M_2,\xi_1\# \xi_2)$ and then ECH decomposes as the tensor product of the corresponding ECH's of the pieces (at least assuming field coefficients).

See the paper Sutures and Contact Homology by Colin-Ghiggini-Honda-Hutchings, in particular Theorem 1.8 and its proof in Section 8.

  It also contains results on sutured manifold decompositions and how ECH respects that -- the maps on ECH under "sutured manifold gluing" are monomorphisms.

I will also use this space to point out that $ECH$, as opposed to the other isomorphic homologies $HF$ and $SWF$, easily handles disconnected manifolds. Roughly, ECH of the disjoint union of two contact 3-manifolds is the tensor product of their ECH's.

Yes, given two contact 3-manifolds $(M_1,\xi_1)$ and $(M_2,\xi_2)$ we can form their contact sum $(M_1\# M_2,\xi_1\# \xi_2)$ and then ECH decomposes as the tensor product of the corresponding ECH's of the pieces (at least assuming field coefficients).

See the paper Sutures and Contact Homology by Colin-Ghiggini-Honda-Hutchings, in particular Theorem 1.8 and its proof in Section 8.

  It also contains results on sutured manifold decompositions and how ECH respects that -- the maps on ECH under "sutured manifold gluing" are monomorphisms.

Yes, given two contact 3-manifolds $(M_1,\xi_1)$ and $(M_2,\xi_2)$ we can form their contact sum $(M_1\# M_2,\xi_1\# \xi_2)$ and then ECH decomposes as the tensor product of the corresponding ECH's of the pieces (at least assuming field coefficients).

See the paper Sutures and Contact Homology by Colin-Ghiggini-Honda-Hutchings, in particular Theorem 1.8 and its proof in Section 8. It also contains results on sutured manifold decompositions and how ECH respects that -- the maps on ECH under "sutured manifold gluing" are monomorphisms.

I will also use this space to point out that $ECH$, as opposed to the other isomorphic homologies $HF$ and $SWF$, easily handles disconnected manifolds. Roughly, ECH of the disjoint union of two contact 3-manifolds is the tensor product of their ECH's.

Source Link
Chris Gerig
  • 17.5k
  • 2
  • 71
  • 116

Yes, given two contact 3-manifolds $(M_1,\xi_1)$ and $(M_2,\xi_2)$ we can form their contact sum $(M_1\# M_2,\xi_1\# \xi_2)$ and then ECH decomposes as the tensor product of the corresponding ECH's of the pieces (at least assuming field coefficients).

See the paper Sutures and Contact Homology by Colin-Ghiggini-Honda-Hutchings, in particular Theorem 1.8 and its proof in Section 8.

It also contains results on sutured manifold decompositions and how ECH respects that -- the maps on ECH under "sutured manifold gluing" are monomorphisms.