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Nov 21, 2014 at 20:05 comment added Frieder Ladisch In fact, this seems to be a duplicate of the question linked by @YemonChoi, only that the question here is formulated a little better. I have made my comment an answer to the old question, which already had an answer. I think this question can be closed as duplicate.
Nov 20, 2014 at 16:37 comment added Nick Gill @FriederLadisch, make this an answer!
Nov 20, 2014 at 0:02 comment added Yemon Choi An earlier question which may be related to this one? mathoverflow.net/questions/186581/…
Nov 19, 2014 at 12:47 comment added Frieder Ladisch The answer is yes, and I think this is clear, once you have shown that there is a well-defined action of $H$ on the conjugacy classes: Let $\varepsilon$ be a primitive $|G|$-th root of unity. Then the Galois group $\Gamma$ of $\mathbb{Q}(\varepsilon)/\mathbb{Q}$ acts on the conjugacy classes, and $H$ is a factor group of $\Gamma $. It is well known and not difficult to show that the orbits of $\Gamma$ are the rational conjugacy classes. (c.f. Serre, Linear Representations of Finite Groups, §12.4.)
Nov 19, 2014 at 10:20 history edited Stefan Kohl CC BY-SA 3.0
Language editing, and added top-level tags.
Nov 19, 2014 at 8:09 history edited Simon Rose CC BY-SA 3.0
used \langle and \rangle instead of < and >
Nov 19, 2014 at 8:03 review First posts
Nov 19, 2014 at 8:05
Nov 19, 2014 at 8:00 history asked elsa haghi CC BY-SA 3.0