Timeline for Does this equation has a closed-form solution for $t$? ($(1-p)\sum_{i=0}^{n}t^i = p\sum_{i=0}^{n}(1-t)^i)$)
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
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| Nov 17, 2014 at 18:35 | comment | added | Robert Israel | Yes, the point is that it factors, and the cubic factor is the one that contains $p$, so that's what you're actually solving. | |
| Nov 17, 2014 at 18:26 | comment | added | joro | @RobertIsrael for n=5 I think I am solving higher degree than cubic, which might be reducible. | |
| Nov 17, 2014 at 18:16 | comment | added | Robert Israel | For $n=5$ you're solving the cubic $${t}^{3}-7\,p{t}^{2}+2\,{t}^{2}+7\,pt+2\,t-7\,p+1$$ | |
| Nov 17, 2014 at 16:50 | history | answered | joro | CC BY-SA 3.0 |