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Jun 15, 2020 at 7:27 history edited CommunityBot
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Nov 17, 2014 at 19:06 answer added Robert Israel timeline score: 2
Nov 17, 2014 at 17:26 comment added Chris Wuthrich The Galois group of the equation for $p=3/5$ and $n=7$ is $S_7$, which is not soluble. So don't expect a solution by radicals for $n=7$.
Nov 17, 2014 at 16:50 answer added joro timeline score: 2
Nov 17, 2014 at 15:36 comment added R B @joro - I have a closed form for $t(3,p)$, would love to hear about $t(5,p)$ !
Nov 17, 2014 at 15:35 comment added joro I think I found closed form for n in {3,5}.
Nov 17, 2014 at 15:33 history edited R B CC BY-SA 3.0
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Nov 17, 2014 at 14:57 history edited R B CC BY-SA 3.0
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Nov 17, 2014 at 14:50 comment added GH from MO Probably not. Most irreducible polynomials of degree $n>4$ have a non-solvable Galois group. Of course it would help if you defined more precisely what you mean by "closed form". Solvability in radicals is equivalent to a solvable Galois group for the polynomial.
Nov 17, 2014 at 14:10 history edited R B CC BY-SA 3.0
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Nov 17, 2014 at 13:47 history asked R B CC BY-SA 3.0