Timeline for Does this equation has a closed-form solution for $t$? ($(1-p)\sum_{i=0}^{n}t^i = p\sum_{i=0}^{n}(1-t)^i)$)
Current License: CC BY-SA 3.0
11 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Jun 15, 2020 at 7:27 | history | edited | CommunityBot |
Commonmark migration
|
|
Nov 17, 2014 at 19:06 | answer | added | Robert Israel | timeline score: 2 | |
Nov 17, 2014 at 17:26 | comment | added | Chris Wuthrich | The Galois group of the equation for $p=3/5$ and $n=7$ is $S_7$, which is not soluble. So don't expect a solution by radicals for $n=7$. | |
Nov 17, 2014 at 16:50 | answer | added | joro | timeline score: 2 | |
Nov 17, 2014 at 15:36 | comment | added | R B | @joro - I have a closed form for $t(3,p)$, would love to hear about $t(5,p)$ ! | |
Nov 17, 2014 at 15:35 | comment | added | joro | I think I found closed form for n in {3,5}. | |
Nov 17, 2014 at 15:33 | history | edited | R B | CC BY-SA 3.0 |
added 258 characters in body
|
Nov 17, 2014 at 14:57 | history | edited | R B | CC BY-SA 3.0 |
deleted 2 characters in body
|
Nov 17, 2014 at 14:50 | comment | added | GH from MO | Probably not. Most irreducible polynomials of degree $n>4$ have a non-solvable Galois group. Of course it would help if you defined more precisely what you mean by "closed form". Solvability in radicals is equivalent to a solvable Galois group for the polynomial. | |
Nov 17, 2014 at 14:10 | history | edited | R B | CC BY-SA 3.0 |
edited body
|
Nov 17, 2014 at 13:47 | history | asked | R B | CC BY-SA 3.0 |