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Mar 19, 2010 at 0:58 comment added Pete L. Clark @Sam: yes, you're right. I fixed it accordingly.
Mar 19, 2010 at 0:57 history edited Pete L. Clark CC BY-SA 2.5
added 167 characters in body
Mar 19, 2010 at 0:52 comment added Sam Derbyshire Beat me to it. The Frobenius isogeny is always purely inseparable though, right? I think you meant that multiplication by $p$ is purely inseparable iff the dual to the Frobenius is inseparable.
Mar 19, 2010 at 0:49 history answered Pete L. Clark CC BY-SA 2.5