Timeline for For an elliptic curve $E/\mathbb{Q}$ can the cohomology group $H^1(\text{Gal}(\mathbb{Q}(E[p])/\mathbb{Q}), E[p])$ be nontrivial?
Current License: CC BY-SA 3.0
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| when toggle format | what | by | license | comment | |
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| Nov 11, 2014 at 12:22 | comment | added | Felipe Voloch | That's true. It only works over the rationals for $p=2$. | |
| Nov 11, 2014 at 12:10 | comment | added | Chris Wuthrich | Over $\mathbb{Q}$, the determinant $G\to \mathbb{F}_p^{\times}$ must be surjective. So your $G$ won't appear as a group for an elliptic curve over $\mathbb{Q}$. | |
| Nov 11, 2014 at 12:02 | history | answered | Felipe Voloch | CC BY-SA 3.0 |