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Timeline for pull-back connection

Current License: CC BY-SA 3.0

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Nov 11, 2021 at 0:48 comment added Sherose If we define by this, then well-definedness problem comes out: for any section, it may admit different linear combinations. So how to prove the definition is independent of choice?
Sep 3, 2019 at 18:21 comment added Ali Taghavi @seub as another counter example $f:\mathbb{R}\to \mathbb{R}\quad f(x)=x^2$ pull back sections are just even functions.
Mar 4, 2019 at 16:01 comment added peter say $F(t_0)=F(t_1)$ is the self-intersection, then let $\varphi_j(t_j)=1$ and $\varphi_j(t_{1-j})=0$ and $\varphi_0+\varphi_1=1$. then in the supports of these coefficients the curve is injective.
Sep 9, 2018 at 17:22 comment added seub Can you prove your first claim? It sounds just false to me. For example, take $F : [0,1] \to B$ a curve with a self-intersection.
Nov 11, 2014 at 7:30 review Late answers
Nov 11, 2014 at 8:29
Nov 11, 2014 at 7:15 review First posts
Nov 11, 2014 at 8:33
Nov 11, 2014 at 7:11 history answered Peter Hochs CC BY-SA 3.0