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Nov 10, 2014 at 19:31 comment added მამუკა ჯიბლაძე I see. Though in fact for a maximal $I$ it is equivalent to $\phi^{-1}(I)=I$...
Nov 10, 2014 at 19:08 history edited Ali Taghavi CC BY-SA 3.0
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Nov 10, 2014 at 19:00 comment added Ali Taghavi @მამუკაჯიბლაძე a unital endomorphism. by invariant I mean $\phi(I)\subset I$.(an algebraic translation of the classical fix point property, according to Gelfand duality.
Nov 10, 2014 at 18:47 comment added მამუკა ჯიბლაძე Is $\phi$ an automorphism or any endomorphism? Under $\phi$ or under $\phi^{-1}$?
Nov 10, 2014 at 17:45 history edited Ali Taghavi CC BY-SA 3.0
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Nov 10, 2014 at 17:31 history asked Ali Taghavi CC BY-SA 3.0