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Mar 10, 2020 at 9:29 history edited gerw CC BY-SA 4.0
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Dec 13, 2014 at 17:08 comment added riem I do agree that is not possible to define the normal derivative for all $H^1$ functions. Well $\Delta u \in H^1(\Omega)^*$ can be defined $\langle \Delta u, v \rangle = \int_\Omega \nabla u \nabla v$. Also $C_c^\infty$ is not dense in $H^1$.
Nov 8, 2014 at 19:26 history answered gerw CC BY-SA 3.0