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Nov 8, 2014 at 19:16 comment added Ali Taghavi So a pre-question:Is the proper analogy of the Withney embedding theorem, true?Every manifold is properly embedded in some $\mathbb{R}^{n}$?
Nov 8, 2014 at 18:48 comment added Ali Taghavi ...such that every NC manifold is the image of some $A_{N}$, for some $N\in \mathbb{N}$?(The analogy for Withney theorem). Thanks again for your answer.
Nov 8, 2014 at 18:46 comment added Ali Taghavi Thank you very much for your interesting answer. So We conclude that every non commutative topological manifold, with the above definition, is necessarily "noncompact",i.e nonunital. Your example is very interesting, however it gives the empty manifold since the multplication of each ideal is identically zero. So the next questions could be:What is an example of a non commutative manifold(non unital non commutative banach algebra)? Is it true to say that the tensor product of two manifold is again a manifold? Are there universal NC manifolds $A_{n}$ such that....
Nov 8, 2014 at 18:25 vote accept Ali Taghavi
Nov 8, 2014 at 17:56 history answered Andreas Thom CC BY-SA 3.0