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Nov 8, 2014 at 19:08 comment added Andreas Thom Maybe $\mathcal A$ simple, but I don't know.
Nov 8, 2014 at 19:06 vote accept Etienne
Nov 8, 2014 at 19:06 comment added Etienne That's fine, many thanks! Just for curiosity's sake, would you know any general condition on the pair $(\mathcal B,\mathcal A)$ ensuring that the answer is "Yes"?
Nov 8, 2014 at 17:30 history answered Andreas Thom CC BY-SA 3.0