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Nov 8, 2014 at 14:53 comment added Venkataramana @Michor: thank you. After reading the ans carefully, I see that you were looing at the 3 dimensional adjoint module.
Nov 8, 2014 at 8:54 comment added Peter Mueller @Venkataramana: So do I. The matrices $A$ are clearly elements from $V$, and as I said in the proof, an orbit of $G$ through $A$ is the conjugacy class $A^G$ ($=\{g^{-1}Ag\;|\;g\in G\}$). If $A$ lies in a submodule $W$, then $A^G\subseteq W$, and then also the $\mathbb F_p$ span of $A^G$ is contained in $W$. But the latter is $V$ for the given matrices $A$.
Nov 8, 2014 at 2:47 comment added Venkataramana Are you looking at the two dimensional rep of $V$? Joel looks at the three dimensional adjoint representation $V$.
Nov 7, 2014 at 23:44 history edited Peter Mueller CC BY-SA 3.0
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Nov 7, 2014 at 20:57 history answered Peter Mueller CC BY-SA 3.0