Timeline for Number of paths through infinite trees with given "growth rates"
Current License: CC BY-SA 3.0
11 events
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May 26, 2021 at 15:31 | vote | accept | usul | ||
Nov 7, 2014 at 11:31 | comment | added | Joel David Hamkins | Yes, I agree. But there is an analogous result, however, for at-most $d$-branching trees $T\subset d^{<\omega}$, using $d^n$ in place of $2^n$. | |
Nov 7, 2014 at 7:52 | comment | added | Douglas Zare | There is an assumption in your first theorem that is not present in the question. Your assumption that there are at most $2$ children of each node makes the question more interesting. Without this, it might be that only the first node has multiple children, in which case the number of branches is countable. | |
Nov 7, 2014 at 2:41 | history | edited | Joel David Hamkins | CC BY-SA 3.0 |
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Nov 7, 2014 at 2:33 | history | edited | Joel David Hamkins | CC BY-SA 3.0 |
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Nov 7, 2014 at 2:15 | comment | added | Joel David Hamkins | There is an unsettled middle ground for growth rates between $o(2^n)$ and $\Omega(2^n)$, and it isn't clear to me what is going on there. | |
Nov 7, 2014 at 2:05 | history | edited | Joel David Hamkins | CC BY-SA 3.0 |
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Nov 7, 2014 at 1:55 | history | edited | Joel David Hamkins | CC BY-SA 3.0 |
More precise positive and negative results
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Nov 7, 2014 at 0:55 | history | edited | Joel David Hamkins | CC BY-SA 3.0 |
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Nov 7, 2014 at 0:50 | history | edited | Joel David Hamkins | CC BY-SA 3.0 |
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Nov 6, 2014 at 22:51 | history | answered | Joel David Hamkins | CC BY-SA 3.0 |