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Oct 30, 2013 at 18:24 history edited Emil Jeřábek CC BY-SA 3.0
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Mar 24, 2010 at 6:55 comment added Douglas S. Stones I think you mean "linearly dependent".
Mar 18, 2010 at 19:58 comment added Robin Chapman Fill in a size $n$ square matrix over $\mathbb{F}_2$ row by row. If the first $n-1$ rows are linearly independent, the whole matrix will have zero determinant. Otherwise the last row will cause the determinant to vanish if its entries satisfy a linear equation; this happens with conditional probability $1/2$.
Mar 18, 2010 at 19:36 comment added Michael Lugo Not that I know of, but I'm hardly an expert on random matrices.
Mar 18, 2010 at 19:34 comment added Tony Huynh Thanks Michael. Is there an elementary proof of why the determinant is more likely to be even than odd?
Mar 18, 2010 at 19:33 vote accept Tony Huynh
Mar 18, 2010 at 19:04 history answered Michael Lugo CC BY-SA 2.5