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Dec 17, 2014 at 16:09 comment added Ben Wieland This question already has nontrivial answers, but trivial answers are useful, too. (1) The tensor product of the symplectic representation with itself is a new PVHS. (2) Every finite index subgroup gives a permutation representation, which is a (boring weight 0) PVHS. Even if they factor through $Sp_{2g}(\mathbb Z)$, they don't come from the defining representation. And the group is residually finite, so many don't.
Nov 5, 2014 at 0:33 answer added Ben Wieland timeline score: 7
Nov 4, 2014 at 22:23 vote accept Dan Petersen
Nov 4, 2014 at 14:26 comment added Peter Samuelson If infinite dimensional representations are ok you can take the ring of functions $\mathcal O(Rep(\pi_1(\Gamma_g),G))$ of the representation variety into some algebraic group $G$. Or you could take the homology of the representation variety.
Nov 4, 2014 at 6:12 answer added Donu Arapura timeline score: 17
Nov 4, 2014 at 0:51 answer added Igor Rivin timeline score: 6
Nov 3, 2014 at 22:16 history asked Dan Petersen CC BY-SA 3.0