Timeline for Can Schwartz-Zippel be formulated for commutative rings instead of fields?
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| Nov 3, 2014 at 19:21 | comment | added | Emil Jeřábek | Maybe I should also stress that the conditions on $S$ are necessary even in the simplest possible case: if $ua=ub$ for distinct $a,b\in S$ and $u\ne0$, the degree $1$ univariate polynomial $u(x-a)$ has at least two zeros in $S$. | |
| Nov 3, 2014 at 18:29 | vote | accept | Thomas Klimpel | ||
| Nov 3, 2014 at 15:59 | history | answered | Emil Jeřábek | CC BY-SA 3.0 |