Timeline for Let $R$ be a $M\times N$ matrix with rational entries, Is $|(R\mathbb{Z}^N)/\mathbb{Z}^M|=|(R^T\mathbb{Z}^M)/\mathbb{Z}^N|$?
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
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| Nov 4, 2014 at 3:27 | comment | added | Amritanshu Prasad | @JohannesHahn Thanks for the corrections :) | |
| Nov 3, 2014 at 23:19 | comment | added | Johannes Hahn | @user26857 There's not much going on with $d_i\mathbb{Z}/\mathbb{Z}$, both are subgroups of $\mathbb{Q}$ and quotients of groups works as usual. (The only wierd thing here is that $\mathbb{Z}$ isn't strictly a subgroup of $d_i\mathbb{Z}$ but that was clarified in the OP as a shorthand notation for $d_i\mathbb{Z} / d_i \mathbb{Z}\cap \mathbb{Z}$) | |
| Nov 3, 2014 at 23:14 | history | edited | Johannes Hahn | CC BY-SA 3.0 |
replaced R by mathbb{Z} and made clear(er) that the d_i are rationals
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| Nov 3, 2014 at 5:33 | history | edited | Amritanshu Prasad | CC BY-SA 3.0 |
added 2 characters in body
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| Nov 3, 2014 at 4:34 | vote | accept | imaboy | ||
| Nov 3, 2014 at 4:17 | history | answered | Amritanshu Prasad | CC BY-SA 3.0 |