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Apr 26, 2023 at 18:48 comment added Satwata Hans I am still interested if there is a possibility of a Schwartz kernel-type theorem for $A$-linear operators. Any leads are appreciated.
Dec 2, 2011 at 10:24 comment added Matthew Daws Sorry; you probably know this. In general $\hom^*_A(E,F)$ does not have a predual-- for example, if $E=F=A$ then $\hom^*_A(A,A)$ is just the multiplier algebra of $A$. If $E=F$ is a "self-dual" module then $\hom^*_A(E,E)$ is a von Neumann algebra, and so does have a predual. This is in Paschke's original paper.
Dec 2, 2011 at 3:13 history edited George Lowther CC BY-SA 3.0
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Mar 18, 2010 at 10:02 history asked Ulrich Pennig CC BY-SA 2.5