Timeline for Maximal minimum of Bessel functions
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 30, 2014 at 15:52 | comment | added | Sergei | Thank you. What I missed. Take such $x=a$ that $J_1(a)=0$. Then inf mod over all n will be zero, not so? | |
| Oct 30, 2014 at 15:07 | comment | added | username | @Sergei It is the correct expression. If you invert the sup and inf, the answer is known: $n\to n^{1/3}\sup_{x>0} |J_n(x)|$ is a monotone function, growing from $0$ to $0.675..$ as $n\to \infty$ from a paper of Landau, J. London Math. Soc. (2) 61 (2000) 197-215. | |
| Oct 30, 2014 at 12:59 | comment | added | Sergei | Is it a correct expression? It means we first take any x, then for this x find inf in n as function of x, and then take sup over x? Or it is better to change sup and inf? | |
| Oct 29, 2014 at 19:09 | answer | added | user64494 | timeline score: 2 | |
| Oct 28, 2014 at 18:29 | history | asked | username | CC BY-SA 3.0 |