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Apr 13, 2017 at 12:19 history edited CommunityBot
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Oct 28, 2014 at 6:48 comment added daOnlyBG @GerryMyerson yeah, I've tried that to no avail, unfortunately. I guess one strategy I haven't attempted (yet) would be to express the sum as a Taylor series a lá Fourier for $e$, and then look for that contradiction.
Oct 28, 2014 at 5:40 comment added Gerry Myerson This won't help much, but you can rewrite the number as $(\log5\log6)/(\log2\log3)$.
Oct 27, 2014 at 22:23 history edited daOnlyBG CC BY-SA 3.0
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Oct 27, 2014 at 21:33 answer added GH from MO timeline score: 8
Oct 27, 2014 at 21:23 comment added Henry Cohn Incidentally, Schanuel's conjecture would imply that this number is transcendental.
Oct 27, 2014 at 21:19 comment added Stefan Kohl One would expect this sum to be transcendental, but even proving irrationality of the sum of two given transcendental numbers tends to be hard.
Oct 27, 2014 at 20:55 review Close votes
Oct 28, 2014 at 0:06
Oct 27, 2014 at 20:44 history edited daOnlyBG CC BY-SA 3.0
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Oct 27, 2014 at 20:43 comment added daOnlyBG Will do. Editing it now.
Oct 27, 2014 at 20:43 comment added Joonas Ilmavirta To make this question more self contained, I would recommend giving the number itself.
Oct 27, 2014 at 20:35 review First posts
Oct 27, 2014 at 20:43
Oct 27, 2014 at 20:32 history asked daOnlyBG CC BY-SA 3.0