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Jun 15, 2020 at 7:27 history edited CommunityBot
Commonmark migration
May 10, 2016 at 4:05 comment added Włodzimierz Holsztyński (Right, infinite dimensional).
May 10, 2016 at 3:34 comment added Mikhail Ostrovskii You are right (but in both statements you need to add "infinite-dimensional"), I actually asked whether one can leave the class of Banach spaces (keeping the homeomorphic type of $\ell_2$) and get something injective.
May 10, 2016 at 3:11 comment added Włodzimierz Holsztyński @MikhailOstrovskii, no separable Banach space is metrically injective. Thus it'd be difficult to show that a separable injective metric space is homemorphic to a Banach space. (All separable Banach spaces are homeomorphic one to another, right?)
May 10, 2016 at 3:08 comment added Włodzimierz Holsztyński @MikhailOstrovskii -- your question would not specialize but complement my question. A topological characterization of injective metric spaces (or of a class) can be used to prove or disprove a homeomorphism theorem.
May 10, 2016 at 2:35 comment added Mikhail Ostrovskii I would suggest to start with a concrete question: is there an injective metric space homeomorphic to an infinite-dimensional separable Hilbert space? For finite-dimensional Hilbert spaces and the Hilbert space of density character continuum the answer is clear: they are homeomorphic to $\ell_\infty^n$ and $\ell_\infty$, respectively. The second statement is a special case of the result of Toruńczyk, H. [Characterizing Hilbert space topology. Fund. Math. 111 (1981), no. 3, 247–262].
May 10, 2016 at 2:18 comment added Paul Fabel Is there a reasonable conjecture as to a plausible answer? ( For example the question at hand reminds me of the following: Are the topological spaces which underly length spaces precisely the metrizable, connected and locally path connected spaces?)
May 10, 2016 at 1:46 history edited Włodzimierz Holsztyński CC BY-SA 3.0
cosmetic non-mth editing.
Oct 24, 2014 at 18:04 comment added Włodzimierz Holsztyński Monomorphism of the metric category of metric spaces are not isometric embeddings (they are just injective metric maps). Thus a pure categorist should take this into account.
Oct 24, 2014 at 18:02 comment added Włodzimierz Holsztyński Isbell introduced (1) injective metric envelope, and (2) proved that the metric envelope of a Banach space is virtually the same as the Banach injective envelope (I rediscovered both a little later).
Oct 24, 2014 at 17:54 comment added Włodzimierz Holsztyński @Ali, there are no non-trivial projective objects in the metric category of all metric spaces (only the empty space and singletons are projective). There are no non-trivial projective objects in the metric category of all bounded metric spaces. And in the metric category of all spaces of diameter $\le 1,\ $ a space $\ (X\ d)\ $ is projective $\ \Leftarrow:\Rightarrow\ d$ is the $\ 0\!-\!1$ metric.
Oct 24, 2014 at 17:47 history edited Włodzimierz Holsztyński CC BY-SA 3.0
non-mathematical detail
Oct 24, 2014 at 16:44 history edited Włodzimierz Holsztyński CC BY-SA 3.0
typo
Oct 24, 2014 at 16:28 history edited Włodzimierz Holsztyński CC BY-SA 3.0
A clearer(?) question.
Oct 24, 2014 at 16:19 comment added Ali Taghavi @WłodzimierzHolsztyński Are there some known results about projective metric space with reversing the arrows in your definition? moreover, what is a relation with "functional analysis? I s it a good idea to translate this property for (commutative) separable $C^{*}$ ?
Oct 24, 2014 at 16:14 history edited Włodzimierz Holsztyński CC BY-SA 3.0
A clearer(?) question.
Oct 24, 2014 at 15:54 history edited Włodzimierz Holsztyński CC BY-SA 3.0
typos
Oct 24, 2014 at 15:48 answer added Tom Leinster timeline score: 3
Oct 24, 2014 at 12:06 comment added Andrej Bauer Do you mean: "Characterize those topological spaces which are homeomorphic to an injective metric space?" or "Characterize those metric spaces which are injective, but only in terms of their topological properties?"
Oct 24, 2014 at 12:02 answer added Andrej Bauer timeline score: 0
Oct 24, 2014 at 6:31 history edited Włodzimierz Holsztyński
metric spaces tag
Oct 24, 2014 at 6:16 history edited Włodzimierz Holsztyński CC BY-SA 3.0
necessary details missing (the same sense).
Oct 24, 2014 at 6:14 comment added Włodzimierz Holsztyński Just in case, don't worry about spaces which are not complete--they are never injective. A non-complete space is not a retract of its completion.
Oct 24, 2014 at 6:10 history asked Włodzimierz Holsztyński CC BY-SA 3.0