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Apr 13, 2017 at 12:19 history edited CommunityBot
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Oct 27, 2014 at 8:08 vote accept Dominic van der Zypen
Oct 24, 2014 at 13:11 answer added Ramiro de la Vega timeline score: 4
Oct 23, 2014 at 20:53 comment added Henno Brandsma Aren't there $2^{{2^\kappa}}$ many non-homeomorphic spaces of size $\kappa$ and only $2^\kappa$ many equivalence relations? Then a counting argument would work.
Oct 23, 2014 at 14:08 history edited Dominic van der Zypen
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Oct 23, 2014 at 12:08 history asked Dominic van der Zypen CC BY-SA 3.0