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Let $q$ denote a quadratic form over a field $k$.

The u-invariant of a field $u(k)$ is defined by $u(k):=\{ max (\mathrm{rank}(q)) $ | $ q $ is anisotropic over $k\}$.

Let $k = \mathbb{Q}_p$ for any prime $p$ and set

$L = k(t_1,..,t_n)$.

It is known that $u(k)=4$ and newer results by David B. Leep state that

$u(L) = 4\cdot2^n = 2^{n+2}$.

As a consequence from the Arason-Pfister Hauptsatz we have that

$2^{cd(L)} \leq u(L) = 2^{n+2}$, while $cd(L)$ denotes the cohomological dimension of $L$.

Is $cd(L) = n+2$ i.e. does equality hold in the upper equation?

This question is not trivial in general as Serre points out by mentioning results of Merkurjev in Galois Cohomology. Merkurjev constructs fields $k$ with $cd(k)=2$ having any desired even $u(k) \geq 2^2$$u(k) \geq 2$.

Let $q$ denote a quadratic form over a field $k$.

The u-invariant of a field $u(k)$ is defined by $u(k):=\{ max (\mathrm{rank}(q)) $ | $ q $ is anisotropic over $k\}$.

Let $k = \mathbb{Q}_p$ for any prime $p$ and set

$L = k(t_1,..,t_n)$.

It is known that $u(k)=4$ and newer results by David B. Leep state that

$u(L) = 4\cdot2^n = 2^{n+2}$.

As a consequence from the Arason-Pfister Hauptsatz we have that

$2^{cd(L)} \leq u(L) = 2^{n+2}$, while $cd(L)$ denotes the cohomological dimension of $L$.

Is $cd(L) = n+2$ i.e. does equality hold in the upper equation?

This question is not trivial in general as Serre points out by mentioning results of Merkurjev in Galois Cohomology. Merkurjev constructs fields $k$ with $cd(k)=2$ having any desired even $u(k) \geq 2^2$.

Let $q$ denote a quadratic form over a field $k$.

The u-invariant of a field $u(k)$ is defined by $u(k):=\{ max (\mathrm{rank}(q)) $ | $ q $ is anisotropic over $k\}$.

Let $k = \mathbb{Q}_p$ for any prime $p$ and set

$L = k(t_1,..,t_n)$.

It is known that $u(k)=4$ and newer results by David B. Leep state that

$u(L) = 4\cdot2^n = 2^{n+2}$.

As a consequence from the Arason-Pfister Hauptsatz we have that

$2^{cd(L)} \leq u(L) = 2^{n+2}$, while $cd(L)$ denotes the cohomological dimension of $L$.

Is $cd(L) = n+2$ i.e. does equality hold in the upper equation?

This question is not trivial in general as Serre points out by mentioning results of Merkurjev in Galois Cohomology. Merkurjev constructs fields $k$ with $cd(k)=2$ having any desired even $u(k) \geq 2$.

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nxir
  • 1.5k
  • 8
  • 14

Let $k = \mathbb{Q}_p$ for any prime$q$ denote a quadratic form over a field $p$ and set

$L = k(t_1,..,t_n)$$k$.

The u-invariant of a field $u(k)$ is defined by $u(k):=\{ max (\mathrm{rank}(q)) $ | $ q $ is anisotropic over $k\}$.

Let $k = \mathbb{Q}_p$ for any prime $p$ and set

$L = k(t_1,..,t_n)$.

It is known that $u(k)=4$ and newer results by David B. Leep state that

$u(L) = 4\cdot2^n = 2^{n+2}$.

As a consequence from the Arason-Pfister Hauptsatz we have that

$2^{cd(L)} \leq u(L) = 2^{n+2}$, while $cd(L)$ denotes the cohomological dimension of $L$.

Is $cd(L) = n+2$ i.e. does equality hold in the upper equation?

This question is not trivial in general as Serre points out by mentioning results of Merkurjev in Galois Cohomology. Merkurjev constructs fields $k$ with $cd(k)=2$ having any desired even $u(k) \geq 2^2$.

Let $k = \mathbb{Q}_p$ for any prime $p$ and set

$L = k(t_1,..,t_n)$.

The u-invariant of a field $u(k)$ is defined by $u(k):=\{ max (\mathrm{rank}(q)) $ | $ q $ is anisotropic over $k\}$.

It is known that $u(k)=4$ and newer results by David B. Leep state that

$u(L) = 4\cdot2^n = 2^{n+2}$.

As a consequence from the Arason-Pfister Hauptsatz we have that

$2^{cd(L)} \leq u(L) = 2^{n+2}$, while $cd(L)$ denotes the cohomological dimension of $L$.

Is $cd(L) = n+2$ i.e. does equality hold in the upper equation?

This question is not trivial in general as Serre points out by mentioning results of Merkurjev in Galois Cohomology. Merkurjev constructs fields $k$ with $cd(k)=2$ having any desired even $u(k) \geq 2^2$.

Let $q$ denote a quadratic form over a field $k$.

The u-invariant of a field $u(k)$ is defined by $u(k):=\{ max (\mathrm{rank}(q)) $ | $ q $ is anisotropic over $k\}$.

Let $k = \mathbb{Q}_p$ for any prime $p$ and set

$L = k(t_1,..,t_n)$.

It is known that $u(k)=4$ and newer results by David B. Leep state that

$u(L) = 4\cdot2^n = 2^{n+2}$.

As a consequence from the Arason-Pfister Hauptsatz we have that

$2^{cd(L)} \leq u(L) = 2^{n+2}$, while $cd(L)$ denotes the cohomological dimension of $L$.

Is $cd(L) = n+2$ i.e. does equality hold in the upper equation?

This question is not trivial in general as Serre points out by mentioning results of Merkurjev in Galois Cohomology. Merkurjev constructs fields $k$ with $cd(k)=2$ having any desired even $u(k) \geq 2^2$.

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nxir
  • 1.5k
  • 8
  • 14

Let $k = \mathbb{Q}_p$ for any prime $p$ and set

$L = k(t_1,..,t_n)$.

The u-invariant of a field $u(k)$ is defined by $u(k):=\{ max (\mathrm{rank}(q)) $ | $ q $ is anisotropic over $k\}$.

It is known that $u(k)=4$ and newer results by David B. Leep state that

$u(L) = 4\cdot2^n = 2^{n+2}$.

As a consequence from the Arason-Pfister Hauptsatz we have that

$2^{cd(L)} \leq u(L) = 2^{n+2}$, while $cd(L)$ denotes the cohomological dimension of $L$.

Is $cd(L) = n+2$ i.e. does equality hold in the upper equation?

This question is not trivial in general as Serre points out by mentioning results of Merkurjev in Galois Cohomology. Merkurjev constructs fields $k$ with $cd(k)=2$ having any desired even $u(k) \geq 2^2$.

Let $k = \mathbb{Q}_p$ for any prime $p$ and set

$L = k(t_1,..,t_n)$.

It is known that $u(k)=4$ and newer results by David B. Leep state that

$u(L) = 4\cdot2^n = 2^{n+2}$.

As a consequence from the Arason-Pfister Hauptsatz we have that

$2^{cd(L)} \leq u(L) = 2^{n+2}$, while $cd(L)$ denotes the cohomological dimension of $L$.

Is $cd(L) = n+2$ i.e. does equality hold in the upper equation?

This question is not trivial in general as Serre points out by mentioning results of Merkurjev in Galois Cohomology. Merkurjev constructs fields $k$ with $cd(k)=2$ having any desired even $u(k) \geq 2^2$.

Let $k = \mathbb{Q}_p$ for any prime $p$ and set

$L = k(t_1,..,t_n)$.

The u-invariant of a field $u(k)$ is defined by $u(k):=\{ max (\mathrm{rank}(q)) $ | $ q $ is anisotropic over $k\}$.

It is known that $u(k)=4$ and newer results by David B. Leep state that

$u(L) = 4\cdot2^n = 2^{n+2}$.

As a consequence from the Arason-Pfister Hauptsatz we have that

$2^{cd(L)} \leq u(L) = 2^{n+2}$, while $cd(L)$ denotes the cohomological dimension of $L$.

Is $cd(L) = n+2$ i.e. does equality hold in the upper equation?

This question is not trivial in general as Serre points out by mentioning results of Merkurjev in Galois Cohomology. Merkurjev constructs fields $k$ with $cd(k)=2$ having any desired even $u(k) \geq 2^2$.

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