Skip to main content
11 events
when toggle format what by license comment
Oct 22, 2014 at 14:51 comment added joro From rationals you can scale to integers by multiplying by the lcm of the denominators. If all integers are positive and $\sum x_i < 2^n$ I think there are two equal sum subsets.
Oct 22, 2014 at 14:17 comment added rodms Thanks for your comments, they are very insightful! @joro I'm not concerned about the computability of the decision problem, I just need to know if the set satisfies the distinct subset sums property with some probability!
Oct 22, 2014 at 13:55 comment added Lucia In the additive combinatorics literature such sets are called ``dissociated".
Oct 22, 2014 at 13:18 answer added joro timeline score: 2
Oct 22, 2014 at 13:08 comment added Ben Barber It does not matter whether you allow $I$ and $J$ to intersect, as replacing $I$ by $I \setminus J$ and $J$ by $J \setminus I$ will preserve equality.
Oct 22, 2014 at 13:07 comment added Ben Barber There may be no better name than distinct subset sums.
Oct 22, 2014 at 13:04 comment added joro OK. If you disallow intersection, it is NP-complete over the naturals.
Oct 22, 2014 at 13:03 comment added rodms @joro No, I and J can intersect as long as I \neq J.
Oct 22, 2014 at 12:45 comment added joro Related: oeis.org/A201052
Oct 22, 2014 at 12:38 comment added joro Do you require I and J to have empty intersection?
Oct 22, 2014 at 12:23 history asked rodms CC BY-SA 3.0